-36x+240+2x^2+10x=180

Solution for -36x+240+2x^2+10x=180 equation:

-36x+240+2x^2+10x=180

We move all terms to the left:

-36x+240+2x^2+10x-(180)=0

We add all the numbers together, and all the variables

2x^2-26x+60=0

a = 2; b = -26; c = +60;
Δ = b2-4ac
Δ = -262-4·2·60
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-14}{2*2}=\frac{12}{4}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+14}{2*2}=\frac{40}{4}
=10
$